(4x-7)^2=-7(7-4x)

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Solution for (4x-7)^2=-7(7-4x) equation: 



(4x-7)^2=-7(7-4x)

We move all terms to the left:

(4x-7)^2-(-7(7-4x))=0

We add all the numbers together, and all the variables

(4x-7)^2-(-7(-4x+7))=0



We calculate terms in parentheses: -(-7(-4x+7)), so:

-7(-4x+7)

We multiply parentheses

28x-49

Back to the equation:

-(28x-49)



We get rid of parentheses

(4x-7)^2-28x+49=0

We add all the numbers together, and all the variables

-28x+(4x-7)^2+49=0

We move all terms containing x to the left, all other terms to the right

-28x+(4x-7)^2=-49

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